**Theorem 1 ** : 3=4
**Proof**: Suppose
a + b = c
This can also be written as
4a - 3a + 4b - 3b = 4c - 3c
4a + 4b - 4c = 3a + 3b - 3c
Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)
Remove the same term left and right:
4 = 3

**Theorem 2 **: 1 + 1 = 0
**Proof:** 1 + 1 = 1 + sqrt(1)
= 1 + sqrt[(-1)(-1)]
= 1 + sqrt(-1)sqrt(-1)
= 1 + i * i
= 1 + i ^ 2
= 1 + (-1)
= 0

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