False and joke proofs

Theorem 1  :  3=4    

Proof:  Suppose
         
         a    +    b    =    c

This can also be written as

     4a - 3a + 4b - 3b = 4c - 3c

     4a + 4b - 4c = 3a + 3b - 3c

Take the constants out of the brackets:

     4 * (a+b-c) = 3 * (a+b-c)

Remove the same term left and right:

            4 = 3

Theorem 2 : 1 + 1 = 0

Proof:   1 + 1 = 1 + sqrt(1)

               = 1 + sqrt[(-1)(-1)]

               = 1 + sqrt(-1)sqrt(-1)

               = 1 + i * i

               = 1 + i ^ 2

               = 1 + (-1)

               = 0